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AMC 12 2002b Problem 13

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The sum of 1818 consecutive positive integers is a perfect square. The smallest possible value of this sum is

(A) 169(B) 225(C) 289(D) 361(E) 441\mathrm{(A)}\ 169 \mathrm{(B)}\ 225 \mathrm{(C)}\ 289 \mathrm{(D)}\ 361 \mathrm{(E)}\ 441

Dataset text AMC 12 2000 to 2025. Quoted with source.

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B

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