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AMC 10 2020a Problem 24

  • Paper

Let nn be the least positive integer greater than 10001000 for which gcd⁡(63,n+120)=21andgcd⁡(n+63,120)=60.\gcd(63, n+120) =21 \text{and} \gcd(n+63, 120)=60. What is the sum of the digits of nn? (A) 12(B) 15(C) 18(D) 21(E) 24\textbf{(A) } 12 \textbf{(B) } 15 \textbf{(C) } 18 \textbf{(D) } 21 \textbf{(E) } 24

Dataset text NuminaMath-1.5. Quoted with source.

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18

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