AMC 10 2008b Problem 20

The faces of a cubical die are marked with the numbers $1$, $2$, $2$, $3$, $3$, and $4$. The faces of another die are marked with the numbers $1$, $3$, $4$, $5$, $6$, and $8$. What is the probability that the sum of the top two numbers will be $5$, $7$, or $9$? $\mathrm{(A)}\ 5/18 \mathrm{(B)}\ 7/18 \mathrm{(C)}\ 11/18 \mathrm{(D)}\ 3/4 \mathrm{(E)}\ 8/9$