olymmath

AIME 2023b Problem 15

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For each positive integer nn let ana_n be the least positive integer multiple of 2323 such that an≡1(mod2n).a_n \equiv 1 \pmod{2^n}. Find the number of positive integers nn less than or equal to 10001000 that satisfy an=an+1.a_n = a_{n+1}.

Dataset text AIME 1983 to 2026. Quoted with source.

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