olymmath

AIME 2023a

American Invitational Mathematics Examination 2023.

Paper

Problem 1

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Five men and nine women stand equally spaced around a circle in random order. The probability that every man stands diametrically opposite a woman is mn,\frac{m}{n}, where mm and nn are relatively prime positive integers. Find m+n.m+n.

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Problem 2

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Positive real numbers b≠1b \not= 1 and nn satisfy the equations log⁡bn=log⁡bnandb⋅log⁡bn=log⁡b(bn).\sqrt{\log_b n} = \log_b \sqrt{n} \text{and} b \cdot \log_b n = \log_b (bn). The value of nn is jk,\frac{j}{k}, where jj and kk are relatively prime positive integers. Find j+k.j+k.

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Problem 3

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A plane contains 4040 lines, no 22 of which are parallel. Suppose that there are 33 points where exactly 33 lines intersect, 44 points where exactly 44 lines intersect, 55 points where exactly 55 lines intersect, 66 points where exactly 66 lines intersect, and no points where more than 66 lines intersect. Find the number of points where exactly 22 lines intersect.

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Problem 4

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The sum of all positive integers mm such that 13!m\frac{13!}{m} is a perfect square can be written as 2a3b5c7d11e13f,2^a3^b5^c7^d11^e13^f, where a,b,c,d,e,a,b,c,d,e, and ff are positive integers. Find a+b+c+d+e+f.a+b+c+d+e+f.

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Problem 5

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Let PP be a point on the circle circumscribing square ABCDABCD that satisfies PA⋅PC=56PA \cdot PC = 56 and PB⋅PD=90.PB \cdot PD = 90. Find the area of ABCD.ABCD.

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Problem 6

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Alice knows that 33 red cards and 33 black cards will be revealed to her one at a time in random order. Before each card is revealed, Alice must guess its color. If Alice plays optimally, the expected number of cards she will guess correctly is mn,\frac{m}{n}, where mm and nn are relatively prime positive integers. Find m+n.m+n.

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Problem 7

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Call a positive integer nn extra-distinct if the remainders when nn is divided by 2,3,4,5,2, 3, 4, 5, and 66 are distinct. Find the number of extra-distinct positive integers less than 10001000.

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Problem 8

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Rhombus ABCDABCD has ∠BAD<90∘.\angle BAD < 90^\circ. There is a point PP on the incircle of the rhombus such that the distances from PP to the lines DA,AB,DA,AB, and BCBC are 9,9, 5,5, and 16,16, respectively. Find the perimeter of ABCD.ABCD.

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Problem 9

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Find the number of cubic polynomials p(x)=x3+ax2+bx+c,p(x) = x^3 + ax^2 + bx + c, where a,b,a, b, and cc are integers in {−20,−19,−18,…,18,19,20},\{-20,-19,-18,\ldots,18,19,20\}, such that there is a unique integer m≠2m \not= 2 with p(m)=p(2).p(m) = p(2).

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Problem 10

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There exists a unique positive integer aa for which the sum U=∑n=12023⌊n2−na5⌋U=\sum_{n=1}^{2023}\left\lfloor\dfrac{n^{2}-na}{5}\right\rfloor is an integer strictly between −1000-1000 and 10001000. For that unique aa, find a+Ua+U. (Note that ⌊x⌋\lfloor x\rfloor denotes the greatest integer that is less than or equal to xx.)

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Problem 11

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Find the number of subsets of {1,2,3,…,10}\{1,2,3,\ldots,10\} that contain exactly one pair of consecutive integers. Examples of such subsets are {1,2,5}\{\mathbf{1},\mathbf{2},5\} and {1,3,6,7,10}.\{1,3,\mathbf{6},\mathbf{7},10\}.

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Problem 12

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Let △ABC\triangle ABC be an equilateral triangle with side length 55.55. Points D,D, E,E, and FF lie on BC‾,\overline{BC}, CA‾,\overline{CA}, and AB‾,\overline{AB}, respectively, with BD=7,BD = 7, CE=30,CE=30, and AF=40.AF=40. Point PP inside △ABC\triangle ABC has the property that ∠AEP=∠BFP=∠CDP.\angle AEP = \angle BFP = \angle CDP. Find tan⁡2(∠AEP).\tan^2(\angle AEP).

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Problem 13

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Each face of two noncongruent parallelepipeds is a rhombus whose diagonals have lengths 21\sqrt{21} and 31\sqrt{31}. The ratio of the volume of the larger of the two polyhedra to the volume of the smaller is mn\frac{m}{n}, where mm and nn are relatively prime positive integers. Find m+nm + n. A parallelepiped is a solid with six parallelogram faces such as the one shown below. [asy] unitsize(2cm); pair o = (0, 0), u = (1, 0), v = 0.8dir(40), w = dir(70); draw(o--u--(u+v)); draw(o--v--(u+v), dotted); draw(shift(w)(o--u--(u+v)--v--cycle)); draw(o--w); draw(u--(u+w)); draw(v--(v+w), dotted); draw((u+v)--(u+v+w)); [/asy]

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Problem 14

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The following analog clock has two hands that can move independently of each other. [asy] unitsize(2cm); draw(unitcircle,black+linewidth(2)); for (int i = 0; i < 12; ++i) { draw(0.9dir(30i)--dir(30i)); } for (int i = 0; i < 4; ++i) { draw(0.85dir(90i)--dir(90i),black+linewidth(2)); } for (int i = 1; i < 13; ++i) { label("\small" + (string) i, dir(90 - i * 30) * 0.75); } draw((0,0)--0.6dir(90),black+linewidth(2),Arrow(TeXHead,2bp)); draw((0,0)--0.4dir(90),black+linewidth(2),Arrow(TeXHead,2bp)); [/asy] Initially, both hands point to the number 1212. The clock performs a sequence of hand movements so that on each movement, one of the two hands moves clockwise to the next number on the clock face while the other hand does not move. Let NN be the number of sequences of 144144 hand movements such that during the sequence, every possible positioning of the hands appears exactly once, and at the end of the 144144 movements, the hands have returned to their initial position. Find the remainder when NN is divided by 10001000.

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