olymmath

AIME 2017a Problem 9

  • Paper
  • Answer

Let a10=10a_{10} = 10, and for each positive integer n>10n >10 let an=100an−1+na_n = 100a_{n - 1} + n. Find the least positive n>10n > 10 such that ana_n is a multiple of 9999.

Dataset text AIME 1983 to 2026. Quoted with source.

Show the answer

45

Solutions

No solution is on olymmath yet. Official and human solutions come first when they arrive. AI solutions come after them, with a label.

Add a solution

Locator aime/2017a/p9 · Tag XF001DDNWZ · Edit this page on GitHub · Keys: j next, k previous