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AIME 2016b Problem 6

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For polynomial P(x)=1−13x+16x2P(x)=1-\dfrac{1}{3}x+\dfrac{1}{6}x^{2}, define Q(x)=P(x)P(x3)P(x5)P(x7)P(x9)=∑i=050aixiQ(x)=P(x)P(x^{3})P(x^{5})P(x^{7})P(x^{9})=\sum_{i=0}^{50} a_ix^{i}. Then ∑i=050∣ai∣=mn\sum_{i=0}^{50} |a_i|=\dfrac{m}{n}, where mm and nn are relatively prime positive integers. Find m+nm+n.

Dataset text AIME 1983 to 2026. Quoted with source.

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