Home Competitions AIME 2016b Problem 6
For polynomial P ( x ) = 1 − 1 3 x + 1 6 x 2 P(x)=1-\dfrac{1}{3}x+\dfrac{1}{6}x^{2} P ( x ) = 1 − 3 1 x + 6 1 x 2 , define Q ( x ) = P ( x ) P ( x 3 ) P ( x 5 ) P ( x 7 ) P ( x 9 ) = ∑ i = 0 50 a i x i Q(x)=P(x)P(x^{3})P(x^{5})P(x^{7})P(x^{9})=\sum_{i=0}^{50} a_ix^{i} Q ( x ) = P ( x ) P ( x 3 ) P ( x 5 ) P ( x 7 ) P ( x 9 ) = ∑ i = 0 50 a i x i . Then ∑ i = 0 50 ∣ a i ∣ = m n \sum_{i=0}^{50} |a_i|=\dfrac{m}{n} ∑ i = 0 50 ∣ a i ∣ = n m , where m m m and n n n are relatively prime positive integers. Find m + n m+n m + n .
Dataset text AIME 1983 to 2026 . Quoted with source.
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