olymmath

AIME 2010b

American Invitational Mathematics Examination 2010.

Paper

Problem 1

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Let NN be the greatest integer multiple of 3636 all of whose digits are even and no two of whose digits are the same. Find the remainder when NN is divided by 10001000.

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Problem 2

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A point PP is chosen at random in the interior of a unit square SS. Let d(P)d(P) denote the distance from PP to the closest side of SS. The probability that 15≤d(P)≤13\frac{1}{5}\le d(P)\le\frac{1}{3} is equal to mn\frac{m}{n}, where mm and nn are relatively prime positive integers. Find m+nm+n.

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Problem 3

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Let KK be the product of all factors (b−a)(b-a) (not necessarily distinct) where aa and bb are integers satisfying 1≤a<b≤201\le a < b \le 20. Find the greatest positive integer nn such that 2n2^n divides KK.

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Problem 4

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Dave arrives at an airport which has twelve gates arranged in a straight line with exactly 100100 feet between adjacent gates. His departure gate is assigned at random. After waiting at that gate, Dave is told the departure gate has been changed to a different gate, again at random. Let the probability that Dave walks 400400 feet or less to the new gate be a fraction mn\frac{m}{n}, where mm and nn are relatively prime positive integers. Find m+nm+n.

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Problem 5

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Positive numbers xx, yy, and zz satisfy xyz=1081xyz = 10^{81} and (log⁡10x)(log⁡10yz)+(log⁡10y)(log⁡10z)=468(\log_{10}x)(\log_{10} yz) + (\log_{10}y) (\log_{10}z) = 468. Find (log⁡10x)2+(log⁡10y)2+(log⁡10z)2\sqrt {(\log_{10}x)^2 + (\log_{10}y)^2 + (\log_{10}z)^2}.

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Problem 6

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Find the smallest positive integer nn with the property that the polynomial x4−nx+63x^4 - nx + 63 can be written as a product of two nonconstant polynomials with integer coefficients.

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Problem 7

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Let P(z)=z3+az2+bz+cP(z)=z^3+az^2+bz+c, where aa, bb, and cc are real. There exists a complex number ww such that the three roots of P(z)P(z) are w+3iw+3i, w+9iw+9i, and 2w−42w-4, where i2=−1i^2=-1. Find ∣a+b+c∣|a+b+c|.

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Problem 8

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Let NN be the number of ordered pairs of nonempty sets A\mathcal{A} and B\mathcal{B} that have the following properties: Find NN.

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Problem 9

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Let ABCDEFABCDEF be a regular hexagon. Let GG, HH, II, JJ, KK, and LL be the midpoints of sides ABAB, BCBC, CDCD, DEDE, EFEF, and AFAF, respectively. The segments AH‾\overline{AH}, BI‾\overline{BI}, CJ‾\overline{CJ}, DK‾\overline{DK}, EL‾\overline{EL}, and FG‾\overline{FG} bound a smaller regular hexagon. Let the ratio of the area of the smaller hexagon to the area of ABCDEFABCDEF be expressed as a fraction mn\frac {m}{n} where mm and nn are relatively prime positive integers. Find m+nm + n.

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Problem 10

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Find the number of second-degree polynomials f(x)f(x) with integer coefficients and integer zeros for which f(0)=2010f(0)=2010.

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Problem 12

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Two noncongruent integer-sided isosceles triangles have the same perimeter and the same area. The ratio of the lengths of the bases of the two triangles is 8:78: 7. Find the minimum possible value of their common perimeter.

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Problem 13

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The 5252 cards in a deck are numbered 1,2,⋯ ,521, 2, \cdots, 52. Alex, Blair, Corey, and Dylan each picks a card from the deck without replacement and with each card being equally likely to be picked, The two persons with lower numbered cards form a team, and the two persons with higher numbered cards form another team. Let p(a)p(a) be the probability that Alex and Dylan are on the same team, given that Alex picks one of the cards aa and a+9a+9, and Dylan picks the other of these two cards. The minimum value of p(a)p(a) for which p(a)≥12p(a)\ge\frac{1}{2} can be written as mn\frac{m}{n}. where mm and nn are relatively prime positive integers. Find m+nm+n.

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Problem 14

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Triangle ABCABC with right angle at CC, ∠BAC<45∘\angle BAC < 45^\circ and AB=4AB = 4. Point PP on AB‾\overline{AB} is chosen such that ∠APC=2∠ACP\angle APC = 2\angle ACP and CP=1CP = 1. The ratio APBP\frac{AP}{BP} can be represented in the form p+qrp + q\sqrt{r}, where pp, qq, rr are positive integers and rr is not divisible by the square of any prime. Find p+q+rp+q+r.

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Problem 15

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In triangle ABCABC, AC=13AC = 13, BC=14BC = 14, and AB=15AB=15. Points MM and DD lie on ACAC with AM=MCAM=MC and ∠ABD=∠DBC\angle ABD = \angle DBC. Points NN and EE lie on ABAB with AN=NBAN=NB and ∠ACE=∠ECB\angle ACE = \angle ECB. Let PP be the point, other than AA, of intersection of the circumcircles of △AMN\triangle AMN and △ADE\triangle ADE. Ray APAP meets BCBC at QQ. The ratio BQCQ\frac{BQ}{CQ} can be written in the form mn\frac{m}{n}, where mm and nn are relatively prime positive integers. Find m−nm-n.

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