olymmath

AIME 2009b Problem 9

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Let mm be the number of solutions in positive integers to the equation 4x+3y+2z=20094x+3y+2z=2009, and let nn be the number of solutions in positive integers to the equation 4x+3y+2z=20004x+3y+2z=2000. Find the remainder when m−nm-n is divided by 10001000.

Dataset text AIME 1983 to 2026. Quoted with source.

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