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AIME 2009a Problem 3

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A coin that comes up heads with probability p>0p > 0 and tails with probability 1−p>01 - p > 0 independently on each flip is flipped 88 times. Suppose that the probability of three heads and five tails is equal to 125\frac {1}{25} of the probability of five heads and three tails. Let p=mnp = \frac {m}{n}, where mm and nn are relatively prime positive integers. Find m+nm + n.

Dataset text AIME 1983 to 2026. Quoted with source.

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