Let
p(x,y)=a0+a1x+a2y+a3x2+a4xy+a5y2+a6x3+a7x2y+a8xy2+a9y3.
Suppose that
p(0,0)=p(1,0)=p(−1,0)=p(0,1)=p(0,−1)=p(1,1)=p(1,−1)=p(2,2)=0.
There is a point (ca,cb) for which p(ca,cb)=0 for all such polynomials, where a, b, and c are positive integers, a and c are relatively prime, and c>1. Find a+b+c.