olymmath

AIME 2007a Problem 12

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In isosceles triangle △ABC\triangle ABC, AA is located at the origin and BB is located at (20,0)(20,0). Point CC is in the first quadrant with AC=BCAC = BC and angle BAC=75∘BAC = 75^{\circ}. If triangle ABCABC is rotated counterclockwise about point AA until the image of CC lies on the positive yy-axis, the area of the region common to the original and the rotated triangle is in the form p2+q3+r6+sp\sqrt{2} + q\sqrt{3} + r\sqrt{6} + s, where p,q,r,sp,q,r,s are integers. Find p−q+r−s2\frac{p-q+r-s}2.

Dataset text AIME 1983 to 2026. Quoted with source.

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875

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