olymmath

AIME 2002a Problem 13

  • Paper
  • Answer

In triangle ABCABC the medians AD‾\overline{AD} and CE‾\overline{CE} have lengths 1818 and 2727, respectively, and AB=24AB=24. Extend CE‾\overline{CE} to intersect the circumcircle of ABCABC at FF. The area of triangle AFBAFB is mnm\sqrt{n}, where mm and nn are positive integers and nn is not divisible by the square of any prime. Find m+nm+n.

Dataset text AIME 1983 to 2026. Quoted with source.

Show the answer

63

Solutions

No solution is on olymmath yet. Official and human solutions come first when they arrive. AI solutions come after them, with a label.

Add a solution

Locator aime/2002a/p13 · Tag J8MTQ62RW6 · Edit this page on GitHub · Keys: j next, k previous