olymmath

AIME 2002a Problem 12

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Let F(z)=z+iz−iF(z)=\dfrac{z+i}{z-i} for all complex numbers z≠iz\neq i, and let zn=F(zn−1)z_n=F(z_{n-1}) for all positive integers nn. Given that z0=1137+iz_0=\dfrac{1}{137}+i and z2002=a+biz_{2002}=a+bi, where aa and bb are real numbers, find a+ba+b.

Dataset text AIME 1983 to 2026. Quoted with source.

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