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AIME 1985 Problem 13

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The numbers in the sequence 101101, 104104, 109109, 116116,…\ldots are of the form an=100+n2a_n=100+n^2, where n=1,2,3,…n=1,2,3,\ldots For each nn, let dnd_n be the greatest common divisor of ana_n and an+1a_{n+1}. Find the maximum value of dnd_n as nn ranges through the positive integers.

Dataset text AIME 1983 to 2026. Quoted with source.

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