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AHSME 1999 Problem 15

    Let xx be a real number such that sec⁡x−tan⁡x=2\sec x - \tan x = 2. Then sec⁡x+tan⁡x=\sec x + \tan x = (A) 0.1(B) 0.2(C) 0.3(D) 0.4(E) 0.5\textbf{(A)}\ 0.1 \textbf{(B)}\ 0.2 \textbf{(C)}\ 0.3 \textbf{(D)}\ 0.4 \textbf{(E)}\ 0.5

    Dataset text NuminaMath-1.5. Quoted with source.

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