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AHSME 1996 Problem 24

    The sequence 1,2,1,2,2,1,2,2,2,1,2,2,2,2,1,2,2,2,2,2,1,2,…1, 2, 1, 2, 2, 1, 2, 2, 2, 1, 2, 2, 2, 2, 1, 2, 2, 2, 2, 2, 1, 2,\ldots consists of 11's separated by blocks of 22's with nn 22's in the nthn^{th} block. The sum of the first 12341234 terms of this sequence is (A) 1996(B) 2419(C) 2429(D) 2439(E) 2449\text{(A)}\ 1996 \text{(B)}\ 2419 \text{(C)}\ 2429 \text{(D)}\ 2439 \text{(E)}\ 2449

    Dataset text NuminaMath-1.5. Quoted with source.

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    2419

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