AHSME 1996 Problem 17

In rectangle $ABCD$, angle $C$ is trisected by $\overline{CF}$ and $\overline{CE}$, where $E$ is on $\overline{AB}$, $F$ is on $\overline{AD}$, $BE=6$ and $AF=2$. Which of the following is closest to the area of the rectangle $ABCD$?

$\text{(A)}\ 110 \text{(B)}\ 120 \text{(C)}\ 130 \text{(D)}\ 140 \text{(E)}\ 150$