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AHSME 1996 Problem 15

    Two opposite sides of a rectangle are each divided into nn congruent segments, and the endpoints of one segment are joined to the center to form triangle AA. The other sides are each divided into mm congruent segments, and the endpoints of one of these segments are joined to the center to form triangle BB. [See figure for n=5,m=7n=5, m=7.] What is the ratio of the area of triangle AA to the area of triangle BB?

    (A) 1(B) m/n(C) n/m(D) 2m/n(E) 2n/m\text{(A)}\ 1 \text{(B)}\ m/n \text{(C)}\ n/m \text{(D)}\ 2m/n \text{(E)}\ 2n/m

    Dataset text NuminaMath-1.5. Quoted with source.

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