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AHSME 1995 Problem 26

    In the figure, AB‾\overline{AB} and CD‾\overline{CD} are diameters of the circle with center OO, AB‾⊥CD‾\overline{AB} \perp \overline{CD}, and chord DF‾\overline{DF} intersects AB‾\overline{AB} at EE. If DE=6DE = 6 and EF=2EF = 2, then the area of the circle is

    (A) 23π(B) 472π(C) 24π(D) 492π(E) 25π\mathrm{(A) \ 23 \pi } \mathrm{(B) \ \frac {47}{2} \pi } \mathrm{(C) \ 24 \pi } \mathrm{(D) \ \frac {49}{2} \pi } \mathrm{(E) \ 25 \pi }

    Dataset text NuminaMath-1.5. Quoted with source.

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    24\pi

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