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AHSME 1993 Problem 23

    Points A,B,CA,B,C and DD are on a circle of diameter 11, and XX is on diameter AD‾.\overline{AD}. If BX=CXBX=CX and 3∠BAC=∠BXC=36∘3\angle{BAC}=\angle{BXC}=36^\circ, then AX=AX=

    (A) cos⁡(6∘)cos⁡(12∘)sec⁡(18∘)(B) cos⁡(6∘)sin⁡(12∘)csc⁡(18∘)(C) cos⁡(6∘)sin⁡(12∘)sec⁡(18∘)(D) sin⁡(6∘)sin⁡(12∘)csc⁡(18∘)(E) sin⁡(6∘)sin⁡(12∘)sec⁡(18∘)\text{(A) } \cos(6^\circ)\cos(12^\circ)\sec(18^\circ) \\ \text{(B) } \cos(6^\circ)\sin(12^\circ)\csc(18^\circ) \\ \text{(C) } \cos(6^\circ)\sin(12^\circ)\sec(18^\circ) \\ \text{(D) } \sin(6^\circ)\sin(12^\circ)\csc(18^\circ) \\ \text{(E) } \sin(6^\circ)\sin(12^\circ)\sec(18^\circ)

    Dataset text NuminaMath-1.5. Quoted with source.

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    \cos(6)\sin(12)\csc(18)

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