AHSME 1983 Problem 4

Pdfresizer.com-pdf-convert.png In the adjoining plane figure, sides $AF$ and $CD$ are parallel, as are sides $AB$ and $EF$, and sides $BC$ and $ED$. Each side has length $1$. Also, $\angle FAB = \angle BCD = 60^\circ$. The area of the figure is $\textbf{(A)} \ \frac{\sqrt 3}{2} \textbf{(B)} \ 1 \textbf{(C)} \ \frac{3}{2} \textbf{(D)}\ \sqrt{3} \textbf{(E)}\ 2$ Solution