Home Competitions AHSME 1975 Problem 24
In triangle A B C ABC A B C , ∠ C = θ \angle C = \theta ∠ C = θ and ∠ B = 2 θ \angle B = 2\theta ∠ B = 2 θ , where 0 ∘ < θ < 60 ∘ 0^{\circ} < \theta < 60^{\circ} 0 ∘ < θ < 6 0 ∘ . The circle with center A A A and radius A B AB A B intersects A C AC A C at D D D and intersects B C BC B C , extended if necessary, at B B B and at E E E (E E E may coincide with B B B ). Then E C = A D EC = AD E C = A D
(A) for no values of θ (B) only if θ = 45 ∘ (C) only if 0 ∘ < θ ≤ 45 ∘ (D) only if 45 ∘ ≤ θ ≤ 60 ∘ (E) for all θ such that 0 ∘ < θ < 60 ∘ \textbf{(A)}\ \text{for no values of}\ \theta \textbf{(B)}\ \text{only if}\ \theta = 45^{\circ} \\ \textbf{(C)}\ \text{only if}\ 0^{\circ} < \theta \leq 45^{\circ} \textbf{(D)}\ \text{only if}\ 45^{\circ} \leq \theta \leq 60^{\circ} \\ \textbf{(E)}\ \text{for all}\ \theta\ \text{such that}\ 0^{\circ} < \theta < 60^{\circ} (A) for no values of θ (B) only if θ = 4 5 ∘ (C) only if 0 ∘ < θ ≤ 4 5 ∘ (D) only if 4 5 ∘ ≤ θ ≤ 6 0 ∘ (E) for all θ such that 0 ∘ < θ < 6 0 ∘
Dataset text NuminaMath-1.5 . Quoted with source.
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