olymmath

AHSME 1975 Problem 20

    In the adjoining figure triangle ABCABC is such that AB=4AB = 4 and AC=8AC = 8. IF MM is the midpoint of BCBC and AM=3AM = 3, what is the length of BCBC?

    (A) 226(B) 231(C) 9(D) 4+213(E) not enough information given to solve the problem\textbf{(A)}\ 2\sqrt{26} \textbf{(B)}\ 2\sqrt{31} \textbf{(C)}\ 9 \textbf{(D)}\ 4 + 2\sqrt{13}\\ \textbf{(E)}\ \text{not enough information given to solve the problem}

    Dataset text NuminaMath-1.5. Quoted with source.

    Show the answer

    2\sqrt{31}

    Solutions

    No solution is on olymmath yet. Official and human solutions come first when they arrive. AI solutions come after them, with a label.

    Add a solution

    Similar problems

    These problems have the most words in common with this statement.

    Locator ahsme/1975/p20 · Tag 353G6PGTRH · Edit this page on GitHub · Keys: j next, k previous