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AHSME 1975 Problem 15

    In the sequence of numbers 1,3,2,…1, 3, 2, \ldots each term after the first two is equal to the term preceding it minus the term preceding that. The sum of the first one hundred terms of the sequence is (A) 5(B) 4(C) 2(D) 1(E) −1\textbf{(A)}\ 5 \textbf{(B)}\ 4 \textbf{(C)}\ 2 \textbf{(D)}\ 1 \textbf{(E)}\ -1

    Dataset text NuminaMath-1.5. Quoted with source.

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