Home Competitions AHSME 1975 Problem 13
The equation x 6 − 3 x 5 − 6 x 3 − x + 8 = 0 x^6 - 3x^5 - 6x^3 - x + 8 = 0 x 6 − 3 x 5 − 6 x 3 − x + 8 = 0 (A) no real roots (B) exactly two distinct negative roots (C) exactly one negative root (D) no negative roots, but at least one positive root (E) none of these \textbf{(A)} \text{ no real roots} \\ \textbf{(B)} \text{ exactly two distinct negative roots} \\ \textbf{(C)} \text{ exactly one negative root} \\ \textbf{(D)} \text{ no negative roots, but at least one positive root} \\ \textbf{(E)} \text{ none of these} (A) no real roots (B) exactly two distinct negative roots (C) exactly one negative root (D) no negative roots, but at least one positive root (E) none of these
Dataset text NuminaMath-1.5 . Quoted with source.
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