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AHSME 1974 Problem 15

    If x<−2x<-2, then ∣1−∣1+x∣∣|1-|1+x|| equals (A) 2+x(B) −2−x(C) x(D) −x(E) −2\mathrm{(A)\ } 2+x \mathrm{(B) \ }-2-x \mathrm{(C) \ } x \mathrm{(D) \ } -x \mathrm{(E) \ }-2

    Dataset text NuminaMath-1.5. Quoted with source.

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