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AHSME 1973 Problem 31

    In the following equation, each of the letters represents uniquely a different digit in base ten: (YE)⋅(ME)=TTT(YE) \cdot (ME) = TTT The sum E+M+T+YE+M+T+Y equals (A) 19(B) 20(C) 21(D) 22(E) 24\textbf{(A)}\ 19 \textbf{(B)}\ 20 \textbf{(C)}\ 21 \textbf{(D)}\ 22 \textbf{(E)}\ 24

    Dataset text NuminaMath-1.5. Quoted with source.

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