Home Competitions AHSME 1973 Problem 19
Define n a ! n_a! n a ! for n n n and a a a positive to be
n a ! = n ( n − a ) ( n − 2 a ) ( n − 3 a ) . . . ( n − k a ) n_a ! = n (n-a)(n-2a)(n-3a)...(n-ka) n a ! = n ( n − a ) ( n − 2 a ) ( n − 3 a ) ... ( n − k a )
where k k k is the greatest integer for which n > k a n>ka n > k a . Then the quotient 72 8 ! / 18 2 ! 72_8!/18_2! 7 2 8 ! /1 8 2 ! is equal to
(A) 4 5 (B) 4 6 (C) 4 8 (D) 4 9 (E) 4 12 \textbf{(A)}\ 4^5 \textbf{(B)}\ 4^6 \textbf{(C)}\ 4^8 \textbf{(D)}\ 4^9 \textbf{(E)}\ 4^{12} (A) 4 5 (B) 4 6 (C) 4 8 (D) 4 9 (E) 4 12
Dataset text NuminaMath-1.5 . Quoted with source.
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