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AHSME 1970 Problem 2

    A square and a circle have equal perimeters. The ratio of the area of the circle to the are of the square is (A) 4π(B) π2(C) 41(D) 2π(E) π4\text{(A) } \frac{4}{\pi} \text{(B) } \frac{\pi}{\sqrt{2}} \text{(C) } \frac{4}{1} \text{(D) } \frac{\sqrt{2}}{\pi} \text{(E) } \frac{\pi}{4}

    Dataset text NuminaMath-1.5. Quoted with source.

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    \frac{4}{\pi}

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