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AHSME 1970 Problem 13

    Given the binary operation ⋆\star defined by a⋆b=aba\star b=a^b for all positive numbers aa and bb. Then for all positive a,b,c,na,b,c,n, we have (A) a⋆b=b⋆a (B) a⋆(b⋆c)=(a⋆b)⋆c(C) (a⋆bn)=(a⋆n)⋆b(D) (a⋆b)n=a⋆(bn)(E) None of these\text{(A) } a\star b=b\star a \ \text{(B) } a\star (b\star c)=(a\star b) \star c \\ \text{(C) } (a\star b^n)=(a \star n) \star b \text{(D) } (a\star b)^n =a\star (bn) \\ \text{(E) None of these}

    Dataset text NuminaMath-1.5. Quoted with source.

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