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AHSME 1968 Problem 5

    If f(n)=13n(n+1)(n+2)f(n)=\tfrac{1}{3} n(n+1)(n+2), then f(r)−f(r−1)f(r)-f(r-1) equals: (A) r(r+1)(B) (r+1)(r+2)(C) 13r(r+1)(D) 13(r+1)(r+2)(E )13r(r+1)(2r+1)\text{(A) } r(r+1) \text{(B) } (r+1)(r+2) \text{(C) } \tfrac{1}{3} r(r+1) \\ \text{(D) } \tfrac{1}{3} (r+1)(r+2) \text{(E )} \tfrac{1}{3} r(r+1)(2r+1)

    Dataset text NuminaMath-1.5. Quoted with source.

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