If f(n)=31n(n+1)(n+2), then f(r)−f(r−1) equals:
(A) r(r+1)(B) (r+1)(r+2)(C) 31r(r+1)(D) 31(r+1)(r+2)(E )31r(r+1)(2r+1)
Dataset text NuminaMath-1.5. Quoted with source.
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