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AHSME 1967 Problem 1

    The three-digit number 2a32a3 is added to the number 326326 to give the three-digit number 5b95b9. If 5b95b9 is divisible by 9, then a+ba+b equals (A) 2(B) 4(C) 6(D) 8(E) 9\text{(A)}\ 2 \text{(B)}\ 4 \text{(C)}\ 6 \text{(D)}\ 8 \text{(E)}\ 9

    Dataset text NuminaMath-1.5. Quoted with source.

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