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AHSME 1961 Problem 38

    △ABC\triangle ABC is inscribed in a semicircle of radius rr so that its base ABAB coincides with diameter ABAB. Point CC does not coincide with either AA or BB. Let s=AC+BCs=AC+BC. Then, for all permissible positions of CC: (A) s2≤8r2(B) s2=8r2(C) s2≥8r2(D) s2≤4r2(E) s2=4r2\textbf{(A)}\ s^2\le8r^2 \textbf{(B)}\ s^2=8r^2 \textbf{(C)}\ s^2 \ge 8r^2 \\ \textbf{(D)}\ s^2\le4r^2 \textbf{(E)}\ s^2=4r^2

    Dataset text NuminaMath-1.5. Quoted with source.

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