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AHSME 1961 Problem 3

    If the graphs of 2y+x+3=02y+x+3=0 and 3y+ax+2=03y+ax+2=0 are to meet at right angles, the value of aa is: (A) ±23(B) −23(C) −32(D) 6(E) −6\textbf{(A)}\ \pm \frac{2}{3} \textbf{(B)}\ -\frac{2}{3} \textbf{(C)}\ -\frac{3}{2} \textbf{(D)}\ 6 \textbf{(E)}\ -6

    Dataset text NuminaMath-1.5. Quoted with source.

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    -6

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