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AHSME 1960 Problem 38

    In this diagram ABAB and ACAC are the equal sides of an isosceles △ABC\triangle ABC, in which is inscribed equilateral △DEF\triangle DEF. Designate ∠BFD\angle BFD by aa, ∠ADE\angle ADE by bb, and ∠FEC\angle FEC by cc. Then:

    (A) b=a+c2(B) b=a−c2(C) a=b−c2(D) a=b+c2(E) none of these\textbf{(A)}\ b=\frac{a+c}{2} \textbf{(B)}\ b=\frac{a-c}{2} \textbf{(C)}\ a=\frac{b-c}{2} \textbf{(D)}\ a=\frac{b+c}{2} \textbf{(E)}\ \text{none of these}

    Dataset text NuminaMath-1.5. Quoted with source.

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