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AHSME 1960 Problem 17

    The formula N=8×108×x−3/2N=8 \times 10^{8} \times x^{-3/2} gives, for a certain group, the number of individuals whose income exceeds xx dollars. The lowest income, in dollars, of the wealthiest 800800 individuals is at least: (A) 104(B) 106(C) 108(D) 1012(E) 1016\textbf{(A)}\ 10^4 \textbf{(B)}\ 10^6 \textbf{(C)}\ 10^8 \textbf{(D)}\ 10^{12} \textbf{(E)}\ 10^{16}

    Dataset text NuminaMath-1.5. Quoted with source.

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    10^4

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