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AHSME 1952 Problem 34

    The price of an article was increased p%p\%. Later the new price was decreased p%p\%. If the last price was one dollar, the original price was: (A) 1−p2200(B) 1−p2100(C) one dollar(D) 1−p210000−p2(E) 1000010000−p2\textbf{(A)}\ \frac{1-p^2}{200} \textbf{(B)}\ \frac{\sqrt{1-p^2}}{100} \textbf{(C)}\ \text{one dollar} \\ \textbf{(D)}\ 1-\frac{p^2}{10000-p^2} \textbf{(E)}\ \frac{10000}{10000-p^2}

    Dataset text NuminaMath-1.5. Quoted with source.

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