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AHSME 1952 Problem 27

    The ratio of the perimeter of an equilateral triangle having an altitude equal to the radius of a circle, to the perimeter of an equilateral triangle inscribed in the circle is: (A) 1:2(B) 1:3(C) 1:3(D) 3:2(E) 2:3\textbf{(A)}\ 1:2 \textbf{(B)}\ 1:3 \textbf{(C)}\ 1:\sqrt3 \textbf{(D)}\ \sqrt3:2 \textbf{(E)}\ 2:3

    Dataset text NuminaMath-1.5. Quoted with source.

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    \frac{2}{3}

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