AHSME 1952 Problem 20

If $\frac{x}{y}=\frac{3}{4}$, then the incorrect expression in the following is: $\textbf{(A) \ }\frac{x+y}{y}=\frac{7}{4} \textbf{(B) \ }\frac{y}{y-x}=\frac{4}{1} \textbf{(C) \ }\frac{x+2y}{x}=\frac{11}{3}$ $\textbf{(D) \ }\frac{x}{2y}=\frac{3}{8} \textbf{(E) \ }\frac{x-y}{y}=\frac{1}{4}$