olymmath

AHSME 1952 Problem 12

    The sum to infinity of the terms of an infinite geometric progression is 66. The sum of the first two terms is 4124\frac{1}{2}. The first term of the progression is: (A)  3 or 112(B)  1(C)  212(D)  6(E)  9 or 3\textbf{(A) \ }3 \text{ or } 1\frac{1}{2} \textbf{(B) \ }1 \textbf{(C) \ }2\frac{1}{2} \textbf{(D) \ }6 \textbf{(E) \ }9\text{ or }3

    Dataset text NuminaMath-1.5. Quoted with source.

    Solutions

    No solution is on olymmath yet. Official and human solutions come first when they arrive. AI solutions come after them, with a label.

    Add a solution

    Similar problems

    These problems have the most words in common with this statement.

    Locator ahsme/1952/p12 · Tag 3W1KNJ7PZ9 · Edit this page on GitHub · Keys: j next, k previous