AHSME 1951 Problem 49

The medians of a right triangle which are drawn from the vertices of the acute angles are $5$ and $\sqrt{40}$. The value of the hypotenuse is: $\textbf{(A)}\ 10 \textbf{(B)}\ 2\sqrt{40} \textbf{(C)}\ \sqrt{13} \textbf{(D)}\ 2\sqrt{13} \textbf{(E)}\ \text{none of these}$