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AHSME 1951 Problem 25

    The apothem of a square having its area numerically equal to its perimeter is compared with the apothem of an equilateral triangle having its area numerically equal to its perimeter. The first apothem will be: (A) equal to the second(B) 43 times the second(C) 23 times the second(D) 23 times the second(E) indeterminately related to the second\textbf{(A)}\ \text{equal to the second} \textbf{(B)}\ \frac{4}{3}\text{ times the second} \textbf{(C)}\ \frac{2}{\sqrt{3}}\text{ times the second}\\ \textbf{(D)}\ \frac{\sqrt{2}}{\sqrt{3}}\text{ times the second} \textbf{(E)}\ \text{indeterminately related to the second}

    Dataset text NuminaMath-1.5. Quoted with source.

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