olymmath

AHSME 1951 Problem 16

    If in applying the quadratic formula to a quadratic equation f(x)≡ax2+bx+c=0,f(x) \equiv ax^2 + bx + c = 0, it happens that c=b24ac = \frac{b^2}{4a}, then the graph of y=f(x)y = f(x) will certainly: (A) have a maximum(B) have a minimum\mathrm{(A) \ have\ a\ maximum } \mathrm{(B) \ have\ a\ minimum} (C) be tangent to the x−axis\mathrm{(C) \ be\ tangent\ to\ the\ x-axis} (D) be tangent to the y−axis\mathrm{(D) \ be\ tangent\ to\ the\ y-axis} (E) lie in one quadrant only\mathrm{(E) \ lie\ in\ one\ quadrant\ only}

    Dataset text NuminaMath-1.5. Quoted with source.

    Show the answer

    C

    Solutions

    No solution is on olymmath yet. Official and human solutions come first when they arrive. AI solutions come after them, with a label.

    Add a solution

    Similar problems

    These problems have the most words in common with this statement.

    Locator ahsme/1951/p16 · Tag WHHTRE4339 · Edit this page on GitHub · Keys: j next, k previous