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AHSME 1951 Problem 1

    The percent that MM is greater than NN is: (A) 100(M−N)M(B) 100(M−N)N(C) M−NN(D) M−NN(E) 100(M+N)N(\mathrm{A})\ \frac{100(M-N)}{M} (\mathrm{B})\ \frac{100(M-N)}{N} (\mathrm{C})\ \frac{M-N}{N} (\mathrm{D})\ \frac{M-N}{N} (\mathrm{E})\ \frac{100(M+N)}{N}

    Dataset text NuminaMath-1.5. Quoted with source.

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