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AHSME 1950 Problem 6

    The values of yy which will satisfy the equations 2x2+6x+5y+1=0,2x+y+3=02x^{2}+6x+5y+1=0, 2x+y+3=0 may be found by solving: (A) y2+14y−7=0(B) y2+8y+1=0(C) y2+10y−7=0(D) y2+y−12=0(E) None of these equations\textbf{(A)}\ y^{2}+14y-7=0 \textbf{(B)}\ y^{2}+8y+1=0 \textbf{(C)}\ y^{2}+10y-7=0 \\ \textbf{(D)}\ y^{2}+y-12=0 \textbf{(E)}\ \text{None of these equations}

    Dataset text NuminaMath-1.5. Quoted with source.

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