Home Competitions AHSME 1950 Problem 6
The values of y y y which will satisfy the equations 2 x 2 + 6 x + 5 y + 1 = 0 , 2 x + y + 3 = 0 2x^{2}+6x+5y+1=0, 2x+y+3=0 2 x 2 + 6 x + 5 y + 1 = 0 , 2 x + y + 3 = 0 may be found by solving:
(A) y 2 + 14 y − 7 = 0 (B) y 2 + 8 y + 1 = 0 (C) y 2 + 10 y − 7 = 0 (D) y 2 + y − 12 = 0 (E) None of these equations \textbf{(A)}\ y^{2}+14y-7=0 \textbf{(B)}\ y^{2}+8y+1=0 \textbf{(C)}\ y^{2}+10y-7=0 \\ \textbf{(D)}\ y^{2}+y-12=0 \textbf{(E)}\ \text{None of these equations} (A) y 2 + 14 y − 7 = 0 (B) y 2 + 8 y + 1 = 0 (C) y 2 + 10 y − 7 = 0 (D) y 2 + y − 12 = 0 (E) None of these equations
Dataset text NuminaMath-1.5 . Quoted with source.
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