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AHSME 1950 Problem 4

    Reduced to lowest terms, a2−b2ab−ab−b2ab−a2\frac{a^{2}-b^{2}}{ab} - \frac{ab-b^{2}}{ab-a^{2}} is equal to: (A) ab(B) a2−2b2ab(C) a2(D) a−2b(E) None of these\textbf{(A)}\ \frac{a}{b} \textbf{(B)}\ \frac{a^{2}-2b^{2}}{ab} \textbf{(C)}\ a^{2} \textbf{(D)}\ a-2b \textbf{(E)}\ \text{None of these}

    Dataset text NuminaMath-1.5. Quoted with source.

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