AHSME 1950 Problem 1

If $64$ is divided into three parts proportional to $2$, $4$, and $6$, the smallest part is: $\textbf{(A)}\ 5\frac{1}{3} \textbf{(B)}\ 11 \textbf{(C)}\ 10\frac{2}{3} \textbf{(D)}\ 5 \textbf{(E)}\ \text{None of these answers}$