USAMO 1995 Problem 4 Day 2 a0,a1,a2,…a_{0}, a_{1}, a_{2}, \ldotsa0,a1,a2,… is an infinite sequence of integers such that an−ama_{n}-a_{m}an−am is divisible by n−mn-mn−m for all (unequal) nnn and mmm. For some polynomial p(x)\mathrm{p}(\mathrm{x})p(x) we have p(n)>∣an∣\mathrm{p}(\mathrm{n})>\left|\mathrm{a}_{\mathrm{n}}\right|p(n)>∣an∣ for all n\mathrm{n}n. Show that there is a polynomial q(x)\mathrm{q}(\mathrm{x})q(x) such that q(n)=\mathrm{q}(\mathrm{n})=q(n)= ana_{n}an for all nnn. Dataset text NuminaMath olympiads. Quoted with source. Solutions No solution is on olymmath yet. Official and human solutions come first when they arrive. AI solutions come after them, with a label. Add a solution PreviousProblem 3 NextProblem 5 Locator usamo/1995/p4 · Tag KZ4AG9CVRT · Edit this page on GitHub · Keys: j next, k previous