olymmath

USAMO 1991 Problem 5

  • Day 2
  • Answer

X\mathrm{X} is a point on the side BC\mathrm{BC} of the triangle ABC\mathrm{ABC}. Take the other common tangent (apart from BC\mathrm{BC} ) to the incircles of ABX and ACX which intersects the segments AB and AC. Let it meet AX at Y. Show that the locus of Y\mathrm{Y}, as X\mathrm{X} varies, is the arc of a circle.

Dataset text NuminaMath olympiads. Quoted with source.

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AY = \frac{AB + AC - BC}{2}

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